dmskmax.c (2037B)
1 /** 2 * @license Apache-2.0 3 * 4 * Copyright (c) 2020 The Stdlib Authors. 5 * 6 * Licensed under the Apache License, Version 2.0 (the "License"); 7 * you may not use this file except in compliance with the License. 8 * You may obtain a copy of the License at 9 * 10 * http://www.apache.org/licenses/LICENSE-2.0 11 * 12 * Unless required by applicable law or agreed to in writing, software 13 * distributed under the License is distributed on an "AS IS" BASIS, 14 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 15 * See the License for the specific language governing permissions and 16 * limitations under the License. 17 */ 18 19 #include "stdlib/stats/base/dmskmax.h" 20 #include "stdlib/math/base/assert/is_nan.h" 21 #include "stdlib/math/base/assert/is_positive_zero.h" 22 #include <stdint.h> 23 24 /** 25 * Computes the maximum value of a double-precision floating-point strided array according to a mask. 26 * 27 * @param N number of indexed elements 28 * @param X input array 29 * @param strideX X stride length 30 * @param Mask mask array 31 * @param strideMask Mask stride length 32 * @return output value 33 */ 34 double stdlib_strided_dmskmax( const int64_t N, const double *X, const int64_t strideX, const uint8_t *Mask, const int64_t strideMask ) { 35 double max; 36 int64_t ix; 37 int64_t im; 38 int64_t i; 39 double v; 40 41 if ( N <= 0 ) { 42 return 0.0 / 0.0; // NaN 43 } 44 if ( strideX < 0 ) { 45 ix = (1-N) * strideX; 46 } else { 47 ix = 0; 48 } 49 if ( strideMask < 0 ) { 50 im = (1-N) * strideMask; 51 } else { 52 im = 0; 53 } 54 for ( i = 0; i < N; i++ ) { 55 if ( Mask[ im ] == 0 ) { 56 break; 57 } 58 ix += strideX; 59 im += strideMask; 60 } 61 if ( i == N ) { 62 return 0.0 / 0.0; // NaN 63 } 64 max = X[ ix ]; 65 if ( stdlib_base_is_nan( max ) ) { 66 return 0.0 / 0.0; // NaN 67 } 68 i += 1; 69 for (; i < N; i++ ) { 70 ix += strideX; 71 im += strideMask; 72 if ( Mask[ im ] ) { 73 continue; 74 } 75 v = X[ ix ]; 76 if ( stdlib_base_is_nan( v ) ) { 77 return 0.0 / 0.0; // NaN 78 } 79 if ( v > max || ( v == max && stdlib_base_is_positive_zero( v ) ) ) { 80 max = v; 81 } 82 } 83 return max; 84 }